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Which function's graph has a period of 2? A. y=2 sin 3xB. y = 3 cos2xC. y = cos(x-pi/2)D. y = -4 sin (πx)

User Gix
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2 Answers

4 votes

Answer:

Explanation:

Which function's graph has a period of 2? A. y=2 sin 3xB. y = 3 cos2xC. y = cos(x-example-1
User SpoBo
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3 votes

Solution:

From the given functions,

To find the period of a function, the formula is


Period=(2\pi)/(B)

Where;


\begin{gathered} Period=2 \\ 2=(2\pi)/(B) \\ 2B=2\pi \\ B=\pi \end{gathered}

Where b is the coefficient of x is b,

And the general sine function is


y=sin(Bx-C)+D

From the given functions,

The function's graph that have a period of 2 is the function with the value B = π


y=-4\sin(\pi x)

Hence, the answer is option D

User Brian Kintz
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