Question

Which function's graph has a period of 2? A. y=2 sin 3xB. y = 3 cos2xC. y = cos(x-pi/2)D. y = -4 sin (πx)

Answer 1

Explanation:

Answer 2

From the given functions,

To find the period of a function, the formula is

`Period=(2\pi)/(B)`

Where;

`\begin{gathered} Period=2 \\ 2=(2\pi)/(B) \\ 2B=2\pi \\ B=\pi \end{gathered}`

Where b is the coefficient of x is b,

And the general sine function is

`y=sin(Bx-C)+D`

From the given functions,

The function's graph that have a period of 2 is the function with the value B = π

`y=-4\sin(\pi x)`

Hence, the answer is option D