Question

Given that, g(x) = sin xExplain reason if the question cannot be solved.

Answer 1

Given
`g(x)=sinx;\text{ }\int_{-(\pi)/(2)}^{(\pi)/(2)}g(x)dx`Solution
`\int sinx=-cosx+C`
`\begin{gathered} \int_{-(\pi)/(2)}^{(\pi)/(2)}sinxdx=-cos((\pi)/(2))--cos(-(\pi)/(2)) \\ =-cos((\pi)/(2))+cos(-(\pi)/(2)) \\ \\ =0 \end{gathered}`The final answer
`\int_{-(\pi)/(2)}^{(\pi)/(2)}g(x)dx=0`