Given the arithmetics sequence 2, 24, 46... we are to find the 35th erm of the sequence
The nth term of an arithmetic sequence is expressed as;
Tn = a + (n-1)d where;
a is the first term
n is the number of terms
d is the common difference
From the sequence;
a = 2
d = 24-2 = 46-24 = 22
n =35 (since we are looking for the 35th term)
Substitute this values into the formula;
T35 = 2 +(35-1)(22)
T35 = 2 + (34)(22)
T35 = 2 + 748
T35 = 750
Hence the 35th term of the sequence is 750