Answer:
Explanation:
From the given information:
6 cars pass on the road per minute. This implies that per minute, we will have:
6/60 passes = 0.1 car passing the road per second
Thus, for 5 sec; we have:
5 × 0.1 = 0.5
Let assume X signifies to be a random variable which denote the no of cars in the next 5 minutes and which follows a Poisson distribution.
i.e.
However, the possibility of collision supposes the deer requires 2 seconds to cross the road can be computed as follows:
Suppose Y denote the arbitrary variable that addresses the no. of cars passing the road in 2 secs, then;