Question

Can you please help me solve this I have no clue what to do

Answer 1

The equation thatmodels the movement of the objet is:

`h(t)=16t^2+60t`

where h(t) is equal to the hight and t is the time, so we can replace h(t)=36 so:

`\begin{gathered} 36=16t^2+60t \\ -16t^2+60t-36=0 \end{gathered}`

now we can use the cuadratic function to find the values of t so:

`\begin{gathered} \frac{-b\pm\sqrt[]{b^2-4(a)(c)}}{2a} \\ a=-16 \\ b=60 \\ c=-36 \end{gathered}`

So the equation become:

`\frac{-60\pm\sqrt[]{60^2-4(-16)(-36)}}{2(-16)}`

Now we operate so:

`\begin{gathered} \frac{-60\pm\sqrt[]{3600-2304}}{-32} \\ \frac{-60\pm\sqrt[]{1296}}{-32} \\ (-60\pm36)/(-32) \end{gathered}`

Now we solve bout solutions:

`\begin{gathered} t_1=(-60+36)/(-32)=0.75 \\ t_2=(-60-36)/(-32)=3 \end{gathered}`

So he will reach a hight of 36 feets at 0.75 seconds and a time of 3 seconds because the first time is when his is going up and the second time is we he is falling back to the grownd.