Question

light Incident on air / Glass boundary If the Incident angle IS 42°the Index of refraction of the glass 1.5 what the Refracted angle

Answer 1

Given

The incident angle is

`i=42^o`

The index of refraction is n=1.5

To find

The angle of refraction

Step-by-step explanation

We know,

`\begin{gathered} n=(sini)/(sinr) \\ \Rightarrow1.5=(sin42^0)/(sinr) \\ \Rightarrow sinr=(sin42^o)/(1.5) \\ \Rightarrow sinr=0.44 \\ \Rightarrow r=26.10^o \end{gathered}`

Conclusion

The angle of refraction is 26.10 deg