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Write the quadratic equation in standard form:-4x – 19 = x2

Write the quadratic equation in standard form:-4x – 19 = x2-example-1
User Sjstrutt
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3 votes

Solution

We have the following solution:


x^2+4x+19=0

And we can use the following equation:


x=\frac{-\text{b}\pm\sqrt[]{b^2-4ac}}{2a}

For this case a=1, b=4, c=19

Replacing we got:


x=\frac{-4\pm\sqrt[]{(4)^2-4(1)(19)}}{2(1)}=\frac{-4\pm\sqrt[]{-60}}{2}=-2\pm\sqrt[]{15}i

Then the answers are:


x=-2-\sqrt[]{15}i,-2+\sqrt[]{15}i

User Kaspi
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