Given:
mean of 98 25°F and a standard deviation of 0.68°F.
Required:
Percentage of healthy adults with body temperatures within 1 standard deviation of the mean, or between 97.57°F and 98.93°
Step-by-step explanation:
mean=98.25
98.93-98.25=0.68
97.57-98.25=-0.68
So 97.57°F and 98.93°F are 0.68 standard deviation from the mean 98.25F
By empirical rule we know that 68 % of the data lies within 0.68 standard deviation
of the mean
Required answer:
Above explanation