Question

I don’t know how to do this. Can you help?

Answer 1

Given,

The expression is,

`f(x)=-x^2+2x+5`

Required

The value of f(x) at x = -1, 0, 1, 2, 3.

The value of f(x) when x = -1.

`f(-1)=-(-1)^2+2(-1)+5=2`

The value of f(x) when x = 0.

`f(0)=-(0)^2+2(0)+5=5`

The value of f(x) when x = 1.

`f(1)=-(1)^2+2(1)+5=6`

The value of f(x) when x = 2.

`f(1)=-(2)^2+2(2)+5=5`

The value of f(x) when x = 3.

`f(1)=-(3)^2+2(3)+5=2`

Hence, the value of f(x) at x = -1 , 0,1, 2, 3 is obtained.