A 12.8 mm 110°C find the area of the sector formed

asked Jan 9, 2023 91.6k views

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Since 110 degress is equal to 11pi/18 then the area is

$(12.8)^2((11\pi)/(18))((1)/(2))=(81.92)((11\pi)/(18))=157.275mm^2$

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