Question

Please help. i’m not fully understanding what i’m supposed to solve .

Answer 1

Given:

In a right triangle, ACB

AC=12

CB=9

AB=15

To choose two angles with a cosine ratio of 3/5:

`\begin{gathered} \cos B=(BC)/(AB) \\ \cos B=(9)/(15) \\ \cos B=(3)/(5) \end{gathered}`

Similarly, for a right triangle MPN,

The corresponding angle to angle B is N.

So, the answer is,

Angle B and Angle N.