Question

Find the equation of the line given that is perpendicular/parallel using the point (8,-3)

Answer 1

From -8x +6y = 6, make y the subject. This is because equation of a line is given as y = mx +c, where m is the gradient and c is the intercept.

From -8x + 6y = 6

6y = 6 + 8x

6y = 8x + 6 dividing through by 6, we have

`\begin{gathered} y\text{ = }(8)/(6)x\text{ + }(6)/(6) \\ y\text{ = }(4)/(3)x\text{ + 1} \end{gathered}`