Question

in the figure below, points D, E, and F are the midpoints of the sides of ABC. suppose AB =36, BC =58, and DE =32. find the following lengths

Answer 1

Given data:

The first given length is AB =36.

The second given length is BC =58.

The third given length is DE =32.

The expression for AC length is,

`\begin{gathered} AC=2(DE) \\ =2(32) \\ =64 \end{gathered}`

The expression for DF length is,

`\begin{gathered} DF=(1)/(2)BC \\ =(1)/(2)(58) \\ =29 \end{gathered}`

The expression for CF length is,

`\begin{gathered} CF=(1)/(2)(AC) \\ =(1)/(2)(64) \\ =32 \end{gathered}`

Thus, AC is 64, DF is 29, and CF is 32.