Given that the ride-sharing company has computed its mean fare to be $33.00, with a standard deviation of $4.10, this implies that
![\begin{gathered} \mu=33.00 \\ \sigma=4.10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/hbx8er8p4o69bsrnwdyccvargcj15ozcyk.png)
The z score value is expressed as
![\begin{gathered} z=(x-\mu)/(\sigma) \\ where \\ x\Rightarrow observed\text{ value} \\ \mu\Rightarrow mean\text{ of the sample} \\ \sigma\Rightarrow standard\text{ deviation of the sample} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/nlos96hs124z67ghek4iph69htutjm7dx7.png)
A) Approximately 68% of the company's rides have fares between . . .
From the normal distribution table,
this implies that the z score value is
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