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Consider a regular pyramid where p is the perimeter of the base, s is the slant height, BA is the base area, and LA is the lateral area. What is a valid formula for the surface area? Check all that apply. D A. SA = 2BA+ ' ps D B. SA = BA + 2LA O C. SA = BA + 3pS D D. SA = BA + LA O E. SA = 8• LA

Consider a regular pyramid where p is the perimeter of the base, s is the slant height-example-1
User Lamonte
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Answer:

The valid formula for the surface area are;


\begin{gathered} SA=BA+LA \\ SA=BA+(1)/(2)ps \end{gathered}

Step-by-step explanation:

Given the regular pyramid with;


\begin{gathered} \text{perimeter of base = p} \\ \text{slant height = s} \\ \text{Base area = BA} \\ \text{Lateral area = LA} \end{gathered}

The total surface area is the sum of the Base area and the Lateral area.


SA=BA+LA

And the formula for calculating the lateral area of the pyramid is;


\begin{gathered} LA=(1)/(2)* Perimeter\text{ of base }* slant\text{ height} \\ LA=(1)/(2)ps \end{gathered}

substituting LA into the formula above;


\begin{gathered} SA=BA+LA \\ SA=BA+(1)/(2)ps \end{gathered}

The valid formula for the surface area are;


\begin{gathered} SA=BA+LA \\ SA=BA+(1)/(2)ps \end{gathered}

User Navnd
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