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If the first 5 terms of an infinite geometric sequence are 100, 60,36, 21.6 , and 12.96, then the sum of all the terms in the sequence is _______.

User DanMan
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Solution:

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 3/5 gives the next term. In other words,


a_n\text{ = }a_1r^(n-1)

where r = 3/5. Now, The sum of a series S_n is calculated using the formula:


S_n\text{ = }(a(1-r^n))/(1-r)

For the sum of an infinite geometric series, as n approaches infinity we have that 1-r^n approaches 1. Thus


\text{ }(a(1-r^n))/(1-r)

approaches


\text{ }(a)/(1-r)

then the sum of an infinite geometric series would be:


S_(\infty)=(a)/(1-r)_{}

The values a = 100 and r = 3/5 can be put in the previous equation:


S_(\infty)=(100)/(1-(3)/(5))_{}=\text{ }250

then, the correct answer is:


S_(\infty)=250

User SoZettaSho
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