Answer:
1. Percentage yield is 64.75%
2. Atom economy is 48.39%
Step-by-step explanation:
1. Determination of the percentage yield
Experimental yield = 24.8 g
Theoretical yield = 38.3 g
Percentage yield =?
Percentage yield = Experimental yield /Theoretical yield × 100
Percentage yield = 24.8 / 38.3 × Percentage yield = 2480 / 38.3
Percentage yield = 64.75%
2. Determination of the atom economy.
The balanced equation for the reaction is given below:
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
Next, we shall determine the mass of CO₂, H₂O and C₆H₁₂O₆ from the balanced equation.
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32
= 44 g/mol
Mass of CO₂ from the balanced equation = 6 × 44 = 264 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16
= 18 g/mol
Mass of H₂O from balanced equation = 6 × 18 = 108 g
Molar mass of C₆H₁₂O₆ = (6×12) + (12×1) + (6×16)
= 72 + 12 + 96
= 180 g/mol
Mass of C₆H₁₂O₆ from the balanced equation = 1 × 180 = 180 g
Next, we shall determine the total mass of the reactants. This is illustrated below:
Mass of CO₂ = 264 g
Mass of H₂O = 108 g
Total mass of reactants =?
Total mass of reactant = Mass of CO₂ + Mass of H₂O
Total mass of reactant = 264 + 108
Total mass of reactant = 372 g
Finally, we shall determine the atom economy. This can be obtained as follow:
Mass of desire atom (C₆H₁₂O₆) = 180 g
Total mass of reactants = 372 g
Atom economy =.?
Atom economy = mass of desire atom / total mass of reactant × 100
Atom economy = 180/372 × 100
Atom economy = 48.39%