We have the following equation given:
f(x) = (x+3)^2 -6
The original equation for this case is
f(x) = (x-h)^2 +k
Where h and k represent the coordinates of the vertex
For this special case we can write the general expression like this:
f(x) = (x- (-3))^2 +6
So then we have a :
Shift 3 units to the left and 6 units up