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I need help with this its about balancing chemicals and etc. Picture included

I need help with this its about balancing chemicals and etc. Picture included-example-1
User Sasse
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Compound 1 + Compound 2 ----> Compound 3

+ -----> Lithium oxide (s)

Li (s) + O₂ (g) ------>

Compound 1:

The formula of the compound is Li (s), if we take a look at the periodic table the name of the compound is Lithium.

Compound 2:

Is the well known gas oxygen.

Compound 3:

We have to find the formula of the compound Lithium Oxide. The usual oxidation state of Li is +1, and of O is -2. So the oxide that they form is Li₂O.

Lithium (s) + Oxygen (g) -----> Lithium oxide (s)

Li (s) + O₂ (g) ------> Li₂O (s)

If we take a look at the six types of reactions, we can represent the synthesis reaction like:

A + B -----> AB

So our reaction is a synthesis reaction.

Li (s) + O₂ (g) ------> Li₂O (s)

Initially:

Oxygen: On the reactants side: 2 On the products side: 1

Lithium: On the reactants side: 1 On the products side: 2

First Step:

To balance the oxygen we have to change the coefficient in front of Li₂O (s).

Because we have 2 O on the left and 1 O on the right.

Li (s) + O₂ (g) ------> 2 Li₂O (s)

Now we have balanced the O, let's try to balance the Li:

Li (s) + O₂ (g) ------> 2 Li₂O (s)

Oxygen: On the reactants side: 2 On the products side: 2

Lithium: On the reactants side: 1 On the products side: 4

Second Step:

To balance the Li we have to change the coefficient in front of Li (s), since we have 1 Li on the left and 4 on the right.

4 Li (s) + O₂ (g) ------> 2 Li₂O (s)

Oxygen: On the reactants side: 2 On the products side: 2

Lithium: On the reactants side: 4 On the products side: 4

So it is balanced.

4 Li (s) + O₂ (g) ------> 2 Li₂O (s)

User Pang
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