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Use the following isosceles triangle to find valur of x and the length of ac.

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Given that the triangle is isosceles, we can say that AB = AC. Using the given expressions we can form the following equation.


\begin{gathered} AB=AC \\ 5x+8=7x-6 \end{gathered}

Let's solve for x.


\begin{gathered} 8+6=7x-5x \\ 14=2x \\ x=(14)/(2) \\ x=7 \end{gathered}

Once we have the value of the variable, we can find the length of AC.


\begin{gathered} AC=7x-6 \\ AC=7(7)-6 \\ AC=49-6 \\ AC=43 \end{gathered}

Therefore, the length of AC is 43.

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