Question

Usually potassium hydrogen phthalate is kept very pure. But Stu Dent thinks the bottle of potassium hydrogen phthalate has been accidently mixed with sodium chloride salt. He decides to use a titration to determine the amount of potassium hydrogen phthalate present. He weighs 2.3854 g of the contaminated potassium hydrogen phthalate mixture. The titration uses 17.47 mL of 0.5000 M sodium hydroxide. Use the titration volume and concentration to calculate the moles of potassium hydrogen phthalate actually reacted. Then use the molar mass (204.2 g/mol) to calculate the mass of potassium hydrogen phthalate actually reacted. Enter the mass to 4 significant digits with units of g.

Answer 1

The mass of potassium hydrogen phthalate that reacted in the titration is 1.7834 grams.

Step-by-step explanation:

To calculate the moles of potassium hydrogen phthalate (KHP) that reacted, you use the volume and concentration of the sodium hydroxide (NaOH) solution used in the titration. Using the formula moles = Molarity (M) × Volume (L), you get:

moles of NaOH = 0.5000 M × 0.01747 L = 0.008735 moles of NaOH

Since the reaction between KHP and NaOH is 1:1, the moles of KHP that reacted will also be 0.008735 moles.

To find the mass of KHP that reacted, multiply the moles by its molar mass:

mass of KHP = moles of KHP × molar mass of KHP = 0.008735 moles × 204.2 g/mol

mass of KHP = 1.7834 grams

Answer 2

1.784 g

Step-by-step explanation:

The equation of the reaction is;

NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)

Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M

Number of moles of NaOH reacted =8.735 * 10^-3 moles

From the reaction equation;

1 mole of NaOH reacted with 1 mole of KHC8H4O4

Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.

So,

Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g