Question

A normal distribution has a mean of 82 and a standard deviation of 6. Find the z-score for a data value of 61. Round to two decimal places

Answer 1

- The solution steps are given below:

`\begin{gathered} \text{ The formula for the Z-score is:} \\ Z=(X-\mu)/(\sigma) \\ where, \\ \mu=\text{ Mean} \\ \sigma=\text{ Standard Deviation} \\ X=\text{ The value whose z-score we want to find.} \\ \\ Z=(61-82)/(6) \\ \\ Z=-(21)/(6)=-3.50\text{ \lparen To 2 decimal places\rparen} \end{gathered}`

Final Answer

The answer is -3.50