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I really need help with this one
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1 vote
I really need help with this one

User Darkflame
by
3.8k points

1 Answer

4 votes

we have the expression


\log _6(3x^2-3x)=2

Applying property of logs


(3x^2-3x)=6^2

so

3x^2-3x-36=0

solve the quadratic equation

the values of x are'

x=-3 and x=4

User Ashley Willis
by
3.8k points
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