We know that the diameter of the pipe is 6 feet.
Given that the pipe is cylindrical, we can use the following formula
![V=\pi(r)^2h](https://img.qammunity.org/2023/formulas/mathematics/college/xv9hs8v1e0doolotbxd3uwzk4j6uljqcfh.png)
Where the radius is half the diameter
![r=(d)/(2)=(6ft)/(2)=3ft](https://img.qammunity.org/2023/formulas/mathematics/high-school/i371hc64cegi9joqxu7e8xh5bvxk89ct1l.png)
In this case, the height is represented by the length of the pipe
![h=100ft](https://img.qammunity.org/2023/formulas/mathematics/high-school/o4nxmwxdzweif3rl7sh7sgbcc6j7gnw90a.png)
Replacing all these values, we have
![\begin{gathered} V=3.14(3ft)^2(100ft) \\ V=2,826ft^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8grmyar0dev28wg5qdi0xpq3xoonmvzt1a.png)
Hence, the volume of the pipe is 2,826 cubic feet, approximately.