Question

the Grand Canyon has the average depth of 4000 ft with some sections going to 6000. If you drop an object from a Section 3300 above, how long (in seconds) will it take the object to hit the bottom?

Answer 1

Let's begin by listing out the given information

Average depth (a) = 4000 ft

Peak depth (p) = 6000 ft

Current depth (c) = 3300 ft

To calculate how long it takes the object to hit the bottom, we will use the formula:

`\begin{gathered} \Delta h=(1)/(2)gt^2 \\ g\approx10m/s^2,\Delta h=3300ft \\ 3300=(1)/(2)(10)\cdot t^2 \\ (2\cdot3300)/(10)=t^2 \\ t^2=660 \\ t=\sqrt[]{660}=25.69\approx26 \\ t=26s \end{gathered}`