The volume of a pyramid is given by the following equation:
![V=(1)/(3)A_{\text{base}}\cdot H](https://img.qammunity.org/2023/formulas/mathematics/college/x8lly1229tte8ofss0awyoe1i4orxjtlkr.png)
Knowing that the base of this pyramid is a square, the volume will be:
![V=(1)/(3)L^2\cdot h](https://img.qammunity.org/2023/formulas/mathematics/college/tz7y7eb38equpogn31lx2zaxybnmc5wg38.png)
Recalling that for a square, the area is the square of the length of the sides (L).
We know the perimeter but not the sides, however, for a square, the perimeter is 4 times the lenght of any side, since all sides are equal in length. We can calculate L now:
![\begin{gathered} P=4L \\ L=(P)/(4) \\ L=(4.1m)/(4) \\ L=1.025m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r41ogcwuus1nn6m8x5ol25wnkn9umni3wf.png)
Now, knoing the sides of the base (L=1.025m) and the height of the pyramid (h=3.6m), we can replace values in the equation of the volume:
![\begin{gathered} V=(1)/(3)L^2\cdot h \\ V=(1)/(3)(1.025m)^2\cdot3.6m \\ V\approx1.26m^3 \\ V\approx1.3m^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pce1616pgcxl6lxzc339l4uabxp1xhtxqs.png)
The volume of the pyramid is approximately 1.3 square meters.