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Find the volume of a pyramid with a square base, where the perimeter of the base is4.1 m and the height of the pyramid is 3.6 m. Round your answer to the nearesttenth of a cubic meter.

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The volume of a pyramid is given by the following equation:


V=(1)/(3)A_{\text{base}}\cdot H

Knowing that the base of this pyramid is a square, the volume will be:


V=(1)/(3)L^2\cdot h

Recalling that for a square, the area is the square of the length of the sides (L).

We know the perimeter but not the sides, however, for a square, the perimeter is 4 times the lenght of any side, since all sides are equal in length. We can calculate L now:


\begin{gathered} P=4L \\ L=(P)/(4) \\ L=(4.1m)/(4) \\ L=1.025m \end{gathered}

Now, knoing the sides of the base (L=1.025m) and the height of the pyramid (h=3.6m), we can replace values in the equation of the volume:


\begin{gathered} V=(1)/(3)L^2\cdot h \\ V=(1)/(3)(1.025m)^2\cdot3.6m \\ V\approx1.26m^3 \\ V\approx1.3m^3 \end{gathered}

The volume of the pyramid is approximately 1.3 square meters.

User Srikanth Bhandary
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