Data:
Manoj did 1/10
Kumar did 1/8
Kiran did 1/20
How much work did they finish working together?
Add the fractions as follow:
![\begin{gathered} (a)/(b)\pm(c)/(d)=(ad\pm bc)/(bd) \\ \\ \\ (1)/(10)+(1)/(8)=(8+10)/(80)=(18)/(80)=(9)/(40) \\ \\ (9)/(40)+(1)/(20)=(180+40)/(800)=(220)/(800)=(11)/(40) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qg747liyf6pj579wazm2736zd0ntoijgs4.png)
If the remaining part of the work is finished by Arun, what part of work is done by Arum?
Takes the total work as a unit (1), then subtract 11/40 from 1:
![1-(11)/(40)=(40-11)/(40)=(29)/(40)](https://img.qammunity.org/2023/formulas/mathematics/high-school/j4wl6ciicoyf9qp0nelq4vtl690lexumtc.png)
Then, Arum needs to do 29/40 part of the work to finish it,