The question represents a binomial distribution.
The binomial probability formula is calculated using the formula:
![P(X)=^nC_Xp^X(1-p)^(n-X)](https://img.qammunity.org/2023/formulas/mathematics/college/pu5szvavqyhx3taxetvlddlrxdnxh70hqh.png)
where
P = binomial probability
X = number of times for a specific outcome within n trials
n C x = number of combinations
p = probability of success on a single trial
n = number of trials
From the question, we have the following parameters:
![\begin{gathered} p=30\%=0.3 \\ n=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vfec4inxe49u1xxfp8zrh46rlm1lh3mwwl.png)
We are to evaluate the probability that more than 5 and less than 9, hence:
![P(5<strong>At X = 6:</strong>[tex]\begin{gathered} P(6)=^(10)C_6\cdot0.3^6\cdot(1-0.3)^(10-6) \\ P(6)=0.0368 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9ule57k6fckpwnz9tz4kwfs337x9k1vdso.png)
At X = 7:
![P(7)=0.0090](https://img.qammunity.org/2023/formulas/mathematics/college/aljunzr0l10qr69imk6j10rrputvn85zkb.png)
At X = 8:
![P(8)=0.0014](https://img.qammunity.org/2023/formulas/mathematics/college/xlybts6c8v6wmk4oktj7lf0gxf4xblmz5o.png)
Therefore, the probability will be:
[tex]P(5
The probability is 0.0472.