Question

the sum of three numbers is 78. the second number is twice the first and the third is 3 times the first . find the number

Answer 1

Given

The sum of three numbers is 78.

The second number is twice the first.

The third number is 3 times the first.

Step-by-step explanation

Let the first number be x, second number be y and third number be z.

From the given condition , equations formed are

`x+y+z=78.........................1`
`y=2x.....................2`
`z=3x............................3`

Substitute the values from the equation 2 and 3 in equation 1.

`\begin{gathered} x+2x+3x=78 \\ 6x=78 \\ x=13 \end{gathered}`

Then the first number is 13 and second and third number is determined by substitute the value of x in equation 2 and 3,

`\begin{gathered} y=2*13=26 \\ z=3*13=39 \end{gathered}`Answer

Hence the first number is 13, second number is 26 and third number is 39.