We have a question about probability. Our approach is to obtain the mean amount that can be obtained for the possible outcomes.
Probability is derived as:
![\text{Probability = }\frac{\#\text{ of desired outcome}}{\#\text{ of total outcomes}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ijuplk3kd4tfdbq152xzyezrvlpmh3l3e2.png)
The probability, P of obtaining a white can be derived knowing:
# of desired outcome = 2
# of total outcome = 16
![P=(2)/(16)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/high-school/e728bazpkljxgzu25ungr8sjne7yom9yyd.png)
The average amount obtainable for spinning a white is:
![\mu=(1)/(8)*\text{ \$10=\$1.25}](https://img.qammunity.org/2023/formulas/mathematics/high-school/kds8cj354grat4eersccmhd09vy0gx98f0.png)
The probability, Q of obtaining any other color can be derived knowing:
# of desired outcome = 14
# of total outcome = 16
![P=(14)/(16)=(7)/(8)](https://img.qammunity.org/2023/formulas/mathematics/high-school/f9yea8xs26w8c5buxl3fhp6rvdxq05x58o.png)
The average amount obtainable for spinning any other color is:
![\mu=(7)/(8)*\text{ \$2=\$1.75}](https://img.qammunity.org/2023/formulas/mathematics/high-school/av38nc8mijw3k5sos3ge71d02ican779qb.png)
Net gain on average: Average amount gained - Average amount lost
![\text{ Net gain = \$1.25 - \$1.75 = -\$0.50}](https://img.qammunity.org/2023/formulas/mathematics/high-school/yll2uqgldxv3brfvk77k24kk9hdph1luh1.png)
On average, the player loses 50 cents. That makes it unfavorable for him.
OPTION C