We are given a series circuit with two resistors and a voltage source. Since the resistor are in series this means that the total resistance is the sum of both resistances. Applying Ohm's law we get
![V=I(R_1+R_2)](https://img.qammunity.org/2023/formulas/physics/college/mqwaa09dv9fv4er1co4lc9a5lb43dol1rk.png)
Where:
V is voltage, I is current and R1 and R2 are the resistance of the radio and the variable resistance respectively.
Now we solve for the variable resistance, R2, first by dividing both sides by I:
![(V)/(I)=R_1+R_2](https://img.qammunity.org/2023/formulas/physics/high-school/uwb2w43fzqem8wdw2bv045ez955xeaag7o.png)
Now we subtract R1 to both sides:
![(V)/(I)-R_1=R_2_{}](https://img.qammunity.org/2023/formulas/physics/high-school/5j6ni7t2h33qcd58h5y5m9oo3bsfp8s2my.png)
Replacing the values:
![(15V)/(0.2A)+60O\text{hm}=R_2](https://img.qammunity.org/2023/formulas/physics/high-school/ryzsvnbf3pf189m4ggocru0uoq03ske5oy.png)
Solving the operations:
![\begin{gathered} 75Ohm+60Ohm=R_2 \\ 135Ohm=R_2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/9n5f7fol83giin1hc9branr49ovarp0wht.png)
Therefore, the resistance needed is 135 Ohms.