Question

How much heat is required to raise 50 grams of water from 13 degrees C to 88 degrees C?H2O(s)= 2.108 J/g×kH2O(l)= 4.185 J/g×kH2O(g)= 1.996 J/g×kA. 16kJB. -16kJC. 8 kJ

Answer 1

Step-by-step explanation:

We have to find the amount of heat that is required to raise 50 g of water from 13 °C to 88 °C. If we want to find the amount of heat the formula that we have to use is:

Q = m * C * ΔT

Where Q is the amount of heat, m is the mass, C is the specific heat and ΔT is the temperature change.

m = 50 g

C = 4.185 J/(g*K) (since at 13 °C and 50°C is in liquid state)

ΔT = T final - Tinitial

ΔT = 88 °C - 13 °C = 75 °C

ΔT = 75 °C or 75 K

Now we can replace these values in the formula and get the answer to our problem.

Q = m * C * ΔT

Q = 50 g * 4.185 J/(g*K) * 75 K

Q = 15693 J = 16 kJ

Answer: 16 kJ are required.