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Find all the zeros of the quadratic function:y = x^2 - x - 42Select ALL that apply.Answer choices include:A.) x = -21B.) x = -7C.) x = 2D.) x = 21E.) x = -6F.) x = 6G.) x = 7H.) x = -2

User Majid
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1 Answer

7 votes

Given


y=x^2-x-42

To find the zeros of the function, set y=0 and solve for x. In this case, since the function is a quadratic polynomial, we can use the quadratic formula, as shown below


\begin{gathered} y=0 \\ \Rightarrow x^2-x-42=0 \\ \Rightarrow x=(1\pm√(1+4*42))/(2)=(1\pm13)/(2) \\ \Rightarrow x=7,-6 \end{gathered}

Therefore, the answers are x=-6 and x=7. Options E and G

User Tomas Skogberg
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