A ball is thrown at an angle of 30° off the horizontal, with an initialvelocity of 28 m/s. What is the maximum height the ball will reach?

asked Oct 12, 2023 74.8k views

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5 votes

$sen(30)\ast28=(14m)/(s)$
$\begin{gathered} v^2=(14m/s)^2-2ad \\ (14^2)/(2\ast9.81)=d=9.99m \end{gathered}$

Josephap answered Oct 18, 2023

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