Answer: Provided the graph of distance vs time, we have to answer (a) to (f):
(a) Student's speed from 3rd to the 5th minute:
![S=(\Delta D)/(\Delta t)=(2.5-2.25)/(5-3)=(0.25)/(2)=0.125mi/min](https://img.qammunity.org/2023/formulas/mathematics/college/aky3buaagmh4wx345qolqx5pfr4dlq7vwa.png)
(b) At what time during the bike ride did the student come to stop:
![\begin{gathered} \text{ Between:} \\ 8th\rightarrow11th \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ubv3i6jropk3xghxc0lac58t3xyu63dr4k.png)
(c) During what time interval was the student's speed increasing:
![\begin{gathered} \text{ Between:} \\ \\ 11th\rightarrow14th \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/23uf1x3h6cfbp2smn789pisprud09t78y5.png)
(d) What was the student's speed between 7th to 19th minute:
![S=(\Delta D)/(\Delta t)=(3.8-3.9)/(19-17)=(0.1)/(2)=(0.05mi)/(min)](https://img.qammunity.org/2023/formulas/mathematics/college/vay79xkd7p7nhqm278hdiqeb2a6azhd0hk.png)
(e) During what time interval was the student's speed constant:
![\begin{gathered} \text{ Between the following five time intervals:} \\ 0min-1min \\ 1min-2min \\ 2min-3min \\ 3min-8min \\ 17min-23min \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u4j236is9f9ny5v2kkbef618q9rnygiruw.png)