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16 votes
16 votes
H(j + i) - k5 + h
when h = 3, i = 4, j = 2, and k = 1
pls put how you did it

User Kacper Madej
by
3.3k points

1 Answer

16 votes
16 votes

Answer:

16

Explanation:

First you want to plug in all the numbers where the letters are

h ( j + i )- k(5) + h

3 ( 2 + 4 )- 1(5) + 3

After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.

6 + 12 - 1(5) + 3

Then you just follow PEMDAS to solve for the rest

6 + 12 - 5 + 3

18 - 5 + 3

13 + 3

16

User Saranjith
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2.4k points