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The ratio of the length to the width of a rectangle is 5 to 2. Express the width of the rectangle as a fraction of the perimeter of the rectangle. I am not sure how to help my son do the problem.

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The perimeter of a triangle is given by the following expression:


P=2\cdot(w+l)_{}

Where P is the perimeter, w is the width and l is the length.

We know that the ratio of the length to the width is 5 to 2. This means that for every 5 units of the length there are 2 units of the width, therefore:


5\cdot l=2\cdot w

If we isolate the "l" variable on the left, we have:


l=(2\cdot w)/(5)

We can replace the expression above on the formula for the perimeter.


P=2\cdot((2\cdot w)/(5)+w)_{}

We now need to simplify the right side of the equation and isolate the "w" variable.


\begin{gathered} P=(4w)/(5)+2w \\ P=(4w+10w)/(5) \\ P=(14w)/(5) \\ w=(5P)/(14) \end{gathered}

The width is equal to 5/14 of the perimeter.

User Chef Flambe
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