Question

Barbara, Donna, Cindy, and Nicole ran in a relay race. Their times are listedin the chart below.StudentBarbaraDonnaCindyNicoleХTime(minutes)3102 1/22501. The four girls ran in a relay race as a team. Each girl ran one part ofthe race. The team's total time was 11-mias11 minutes. What was Cindy'stime?

Answer 1

Okay, here we have this:

Considering the provided information, we are going to calculate the requested time and difference, so we obtain the following:

Question 1:

Considering that the total time is equal to the sum of all the times, we obtain that:

`\begin{gathered} 3\text{ }(3)/(10)+2\text{ }(4)/(5)+x+2(1)/(10)=11(3)/(5) \\ (33)/(10)+(14)/(5)+x+(21)/(10)=(58)/(5) \\ x+(14)/(5)+(33)/(10)+(21)/(10)=(58)/(5) \\ x+(14)/(5)+(27)/(5)=(58)/(5) \\ x+(41)/(5)=(58)/(5) \\ x=(17)/(5) \\ x=3\text{ }(2)/(5)\text{ minutes} \end{gathered}`

Finally we obtain that Cindy's time was 3 2/5 minutes.

Question 2:

To calculate the difference between the fastest and the slowest then we will subtract the times of the fast and the slow, so we subtract Nicolle's time from Cindy's:

`\begin{gathered} \text{Difference}=3\text{ }(2)/(5)-2\text{ }(1)/(10) \\ =1+(3)/(10) \\ =1(3)/(10) \end{gathered}`

Finally we obtain that the difference is 1 3/10.