Question

Not a timed or graded assignment. Please use CER format. (Claim, evidence, reasoning) Quick answer = amazing review thank you so much In advance :)

Answer 1

Answer :

Calculations -

1. We are given

• moles of Al2O3 = 9.45 moles

,

• Molar mass of AL2O3 =(2* 26,981539) + (3* 15.999)

= 101,96 g/mol

2. We can calculate the mass of Al2O3 :

`\begin{gathered} \text{Moles = }\frac{mass\text{ Al2O3 }}{\text{Molar mass Al2O3 }} \\ \text{ }\therefore\text{ Mass = Moles }\cdot\text{ Molar Mass } \\ \text{ = 9.45 moles }\cdot\frac{101.96moles}{\text{gram}} \\ \text{ = 963.52 grams } \end{gathered}`

• This means that mass of AL2O3 = 963.52 grams

,

• As a result, Jacob miscalculated the amount of mass of Al2O3 because he divided moles by mol. mass instead of multiplying moles by molar mass .