Question

What would be the molarity of a solution if 500.0mL of a 3.0 M KCl solution is diluted to 3.0L?

Answer 1

0.50 M

Step-by-step explanation

Given:

Initial volume (V1) = 500.0 mL = 0.5 L

Initial molarity (C1) = 3.0 M

Final volume (V2) = 3.0 L

Required: The final molarity (C2)

Solution

C1V1 = C2V2

C2 = C1V1/V2

C2 = (3.0 M x 0.5 L)/3.0 L

C2 = 0.50 M