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What is the solution to the equation below? (Round your answer to twodecimal places.)

What is the solution to the equation below? (Round your answer to twodecimal places-example-1
User Mousa
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1 Answer

3 votes

Hello!

We have the expression:


e^x=7.1

The first step is to write the number as a fraction, look:


e^x=(71)/(10)

Now, let's calculate the natural logarithm on both sides of the equation:


\ln(e^x)=\ln\left(\right.(71)/(70))

We can simplify it as:


\begin{gathered} \cancel{\mathrm{ln}}(\cancel{e}^x)=\operatorname{\ln}((71)/(70)) \\ \\ x=\mathrm{ln}((71)/(70)) \end{gathered}

Now, let's calculate it:


\begin{gathered} x=\ln((71)/(70)) \\ \\ x\cong1.96 \end{gathered}

Answer:

Alternative D. x = 1.96.

User Treffynnon
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