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Given the points A(-4,2) and B(0,-2). Find AB

1 Answer

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AB= 5.65

Step-by-step explanation

when you have 2 points P1 and P2 , the distance between P1 and P2 is given by:


\begin{gathered} \text{distance}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)}^2 \\ where \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

Step 1

Let

P1=A(-4,2)

P2=B(0,-2)

now, replace


\begin{gathered} \text{distance}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)}^2 \\ \text{distance}=\sqrt[]{(0-(-4))^2+(-2-(2)_{})}^2 \\ \text{distance}=\sqrt[]{(4^2)+(-4^2)} \\ \text{distance}=\sqrt[]{16+16} \\ \text{distance}=\sqrt[]{32} \\ \text{distance}=5.65 \end{gathered}

I hope this helps you

Given the points A(-4,2) and B(0,-2). Find AB-example-1
User Elayne
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