1 Answer

Lorenzo Fiamingo · Answer 1 · 2023-03-09T13:46:11+0000

we have

-3x^2-x-3=0

Using the quadratic formula

we have

a=-3

b=-1

c=-3

substitute in the formula

$x=\frac{-(-1)\pm\sqrt[]{-1^2-4(-3)(-3)}}{2(-3)}$
$x=\frac{1\pm\sqrt[]{-35}}{-6}$

Remember that

i^2=-1

so

$x=\frac{1\pm i\sqrt[]{35}}{-6}=x=\frac{-1\pm i\sqrt[]{-35}}{6}$

answer is option B

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