Question

At which values of x does the function F(x) have avertical asymptote? Check all that apply.1F(x) = x(x+5)(x-1)

Answer 1

The given fuction is:

`f(x)=(1)/(x(x+6)(x-1))`

Note that the fuction has a vertica; asymptote when the denomiator of the function equals zero

Hence:

`x(x+6)(x-1)=0`

Solving the equation for x gives:

`\begin{gathered} x=0,x+6=0,x-1=0 \\ x=0,x=-6,x=1 \end{gathered}`

Therefore the required answer is:

`x=0, x=-6, x=1`