Question

In the following reaction, if there were 10 molecules of nitrogen gas (N2), howmany molecules of hydrogen gas (H2) and ammonia gas (NH3) would be presentin the reaction?N2 + 3H2+-> 2NH3N2 = 10; H2 = 30; NH3 = 20N2 = 10; H2 = 30; NH3 = 10N2 = 10; H2 = 800; NH3 = 700N2 = 10; H2 = 60; NH3 = 20

Answer 1

To solve this question we have to use the ratios of the coefficients of the substances.

For hydrogen gas we have that per one molecule of nitrogen, 3 of hydrogen are used. If 10 molecules of nitrogen are used, then we have that:

`10molN_2\cdot(3molH_2)/(molN_2)=30molH_2`

For ammonia gas, per one molecule of nitrogen, 2 of ammonia are produced:

`10molN_2\cdot(2molNH_3)/(molN_2)=20molNH_3`

It means that the correct answer is N2=10; H2=30; NH3=20.