All the alternatives are polynomials. In a polynomial in factored form, each factor corresponds to a zero of the function.
If r is a zeros of the polynomial function, it will have a factor:
![(x-r)](https://img.qammunity.org/2023/formulas/mathematics/college/uzrpo81tgwh13u4pc400ocfyy6kb2io8gb.png)
So, if 0, -3, 2 and -4 are zeros of the polynomial, we have the factors:
![\begin{gathered} (x-0)=x \\ (x-(-3))=(x+3) \\ (x-2) \\ (x-(-4))=(x+4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8ikjsekah6457f543hwlg7exrfz285c6an.png)
So, the function that has these zeros is:
![f(x)=x(x+3)(x-2)(x+4)](https://img.qammunity.org/2023/formulas/mathematics/college/ooflmccaizvgbc8ek93jqhbkstfgonkj5v.png)