Given:
At the city museum, child admission is $5.80 and adult admission is $9.00.
Let the number of children's tickets = x
And the number of the adult tickets = y
on Monday 162 tickets were sold ⇒ x + y = 162
The tickets were sold for a total sale of $1176.40 ⇒ 5.8x + 9y = 1176.40
So, we have the following system of equations:
![\begin{gathered} x+y=162\rightarrow(1) \\ 5.8x+9y=1176.40\rightarrow(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qraakgmur9b6ul2w9674f4v116vgdprd5j.png)
From equation (1) x = 162 - y
substitute (x) into equation (2)
![5.8(162-y)+9y=1176.40](https://img.qammunity.org/2023/formulas/mathematics/college/75dkpeybxzh6177mco9x9ukzw89cxzhtfn.png)
Solve the equation to find (y):
![\begin{gathered} 5.8*162-5.8y+9y=1176.4 \\ 939.6+3.2y=1176.4 \\ 3.2y=1176.4-939.6 \\ 3.2y=236.8 \\ \\ y=(236.8)/(3.2)=74 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/npz9gug5ja6t7r3gxc20qksap9236n3yim.png)
substitute (y) to find (x)
![x=162-74=88](https://img.qammunity.org/2023/formulas/mathematics/college/7gg4tl5wqcoshdy7b3h59e23fj3yracra4.png)
So, the answer will be:
The number of children tickets = 88
The number of adult tickets = 74