The first thing to do is to balance the equation since the number of atoms in the reactants does not coincide with the number of atoms in the products.
So, the balanced equation will be:

So, 2 mol of BF3 reacts with 3 mol of NiCl2 to produce 3 mol of NiF2 and 2 mol of BCl3.
We have 4 mol of NiCl2 so this will be the excess reactant.
Therefore, BF3 will be the limiting reactant.
Before the reaction we will have:
2BF3
3NiCl2 + 1NiCl2(excess)
After the reaction we will have:
3NiF2
2BCl3
1NiCl2
You can produce 3 moles of nickel (II) fluoride and 2 moles of boron chloride.
The limiting reagent is BF3.
The excess reactant is NiCl2. there are 1 moles excess of this reactant.