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A small object of mass 0.500 kg is attached by a 0.870 m - long cord to a pin set into the surface of a frictionless table top. The object moves in a circle on the horizontal surface with a speed of 7.85 m/s. What is the magnitude of the radial acceleration of the object?

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The radial acceleration formula is


a_c=(v^2)/(r)

Where r = 0.870 m and v = 7.85 m/s. Let's replace these values and solve


\begin{gathered} a_c=((7.85m/s)^2)/(0.870m)=(61.62m^2/s^2)/(0.870m)_{} \\ a_c\approx70.83m/s^2 \end{gathered}

Hence, the radial acceleration is around 70.83 m/s2.

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