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Can someone help me with this it's due in tomorrow and I don't know what to do

Can someone help me with this it's due in tomorrow and I don't know what to do-example-1
User Nick Gorham
by
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1 Answer

17 votes
17 votes

Answer:

1) CO₂ :-

Breaking down the masses :-

  • C = 12u
  • O = 16u

What's the sum :-

Mass of C + 2(Mass of O)

⇒ 12u + 2×16u

Relative Formula Mass :-

12u + 2×16u

⇒ 12u + 32u

⇒ 44u

__________________________________________________________

2) CH₄ :-

Breaking down the masses :-

  • C = 12u
  • H = 1u

What's the sum :-

Mass of C + 4(Mass of H)

⇒ 12u + 4×1u

Relative Formula Mass :-

12u + 4×1u

⇒ 12u + 4u

⇒ 16u

__________________________________________________________

3) NH₃ :-

Breaking down the masses :-

  • N = 14u
  • H = 1u

What's the sum :-

Mass of N + 3(Mass of H)

⇒ 14u + 3×1u

Relative Formula Mass :-

14u + 3×1u

⇒ 14u + 3u

⇒ 17u

__________________________________________________________

4) SO₂ :-

Breaking down the masses :-

  • S = 32u
  • O = 16u

What's the sum :-

Mass of S + 2(Mass of O)

⇒ 32u + 2×16u

Relative Formula Mass :-

32u + 2×16u

⇒ 32u + 32u

⇒ 64u

_________________________________________________________

5) CaCO₃ :-

Breaking down the masses :-

  • Ca = 40u
  • C = 12u
  • O = 16u

What's the sum :-

Mass of Ca + Mass of C + 3(Mass of O)

⇒ 40u + 12u + 3×16u

Relative Formula Mass :-

40u + 12u + 3×16u

⇒ 40u + 12u + 48u

⇒ 100u

_________________________________________________________

6) H₂O :-

Breaking down the masses :-

  • H = 1u
  • O = 16u

What's the sum :-

2(Mass of H) + Mass of O

⇒ 2×1u + 16u

Relative Formula Mass :-

2×1u + 16u

⇒ 2u + 16u

⇒ 18u

_________________________________________________________

7) NaCl :-

Breaking down the masses :-

  • Na = 23u
  • Cl = 35.5u

What's the sum :-

Mass of Na + Mass of Cl

⇒ 23u + 35.5u

Relative Formula Mass :-

23u + 35.5u

⇒ 58.5u

_________________________________________________________

8) C₂H₆ :-

Breaking down the masses :-

  • C = 12u
  • H = 1u

What's the sum :-

2(Mass of C) + 6(Mass of H)

⇒ 2×12u + 6×1u

Relative Formula Mass :-

2×12u + 6×1u

⇒ 24u + 6u

⇒ 30u

_________________________________________________________

9) LiOH :-

Breaking down the masses :-

  • Li = 6u
  • O = 16u
  • H = 1u

What's the sum :-

Mass of Li + Mass of O + Mass of H

⇒ 6u + 16u + 1u

Relative Formula Mass :-

6u + 16u + 1u

⇒ 23u

_________________________________________________________

10) H₂SO₄ :-

Breaking down the masses :-

  • H = 1u
  • S = 32u
  • O = 16u

What's the sum :-

2(Mass of H) + Mass of S + 4(Mass of O)

⇒ 2×1u + 32u + 4×16u

Relative Formula Mass :-

2×1u + 32u + 4×16u

⇒ 2u + 32u + 64u

⇒ 98u

User Adriena
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